The problem Orlee solved<\/figcaption><\/figure>\n <\/p>\n
Orlee’s solution:<\/strong><\/p>\nThere will be 5 different degree measures represented.<\/p>\n
This goal is to find the angles that must be congruent to one another.<\/p>\n
First, because I know that vertical angles are congruent, I identified which angles were congruent to which other angles using that theorem.<\/p>\n
7 is congruent to 9
\n8 is congruent to 10
\n12 is congruent to 14
\n11 is congruent to 13
\n2 is congruent to 5
\n1 is congruent to 4
\n3 is congruent to 6<\/p>\n
Because alternate interior angles are congruent, 8 is also congruent to 6 and therefore the measures of 8, 6, 10, and 3 are all equal. Also, 4 is congruent to 11, so the measures of 4, 11, 1, and 13 are all congruent.<\/p>\n
So all in all:<\/p>\n
4 = 11 = 1 = 13
\n8 = 6 = 3 = 10
\n7 = 9
\n12 = 14
\n2 = 5<\/p>\n
The transversals aren’t parallel so there are no corresponding angles that could be congruent. (The measure of Angle 1 + the measure of Angle 2 is equals the measure of Angle 7, but no congruency there!)<\/p>\n
After counting up the different measures, there are 5 different numbers represented.<\/p>\n","protected":false},"excerpt":{"rendered":"
Every week, the Drexel University Math Forum web site poses a math question to their participants. Recently, the site asked their viewers to determine the measures of various angles formed by a pair of parallel lines and two transversals. Orlee Marini-Rapoport, an eighth grade student in Kathryn Hill\u2019s Geometry Honors class, used what she had … Continue reading Orlee’s Solution Gets Posted by Drexel!<\/span> →<\/span><\/a><\/p>\n","protected":false},"author":53,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_exactmetrics_skip_tracking":false,"_exactmetrics_sitenote_active":false,"_exactmetrics_sitenote_note":"","_exactmetrics_sitenote_category":0,"_s2mail":"yes","jetpack_post_was_ever_published":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":true,"jetpack_social_options":{"image_generator_settings":{"template":"highway","enabled":false},"version":2}},"categories":[3],"tags":[188,189],"class_list":["post-897","post","type-post","status-publish","format-standard","hentry","category-math-news","tag-drexel","tag-geometry"],"jetpack_publicize_connections":[],"aioseo_notices":[],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"jetpack_shortlink":"https:\/\/wp.me\/p4GnmO-et","_links":{"self":[{"href":"https:\/\/willistonblogs.com\/math\/wp-json\/wp\/v2\/posts\/897"}],"collection":[{"href":"https:\/\/willistonblogs.com\/math\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/willistonblogs.com\/math\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/willistonblogs.com\/math\/wp-json\/wp\/v2\/users\/53"}],"replies":[{"embeddable":true,"href":"https:\/\/willistonblogs.com\/math\/wp-json\/wp\/v2\/comments?post=897"}],"version-history":[{"count":3,"href":"https:\/\/willistonblogs.com\/math\/wp-json\/wp\/v2\/posts\/897\/revisions"}],"predecessor-version":[{"id":901,"href":"https:\/\/willistonblogs.com\/math\/wp-json\/wp\/v2\/posts\/897\/revisions\/901"}],"wp:attachment":[{"href":"https:\/\/willistonblogs.com\/math\/wp-json\/wp\/v2\/media?parent=897"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/willistonblogs.com\/math\/wp-json\/wp\/v2\/categories?post=897"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/willistonblogs.com\/math\/wp-json\/wp\/v2\/tags?post=897"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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